Respuesta :
What grade of math is this. I suck at math so sorry can't help you dude
1st let's calculate the time needed to reach the maximum distance
h(t) = - 1/2 gt² + v₀t + h₀
h(t) = - 1/2 (9.8).t² + 110.t + 2 ; h(t) = -4.9.t² +110.t + 2
The time needed to reach the maximum height is when the derivative
of h(t) is equal to 0:
h'(t) = 2(-4.9).t + 110 → h'(t) = -9.8.t + 110 = 0 and t = 11.22 seconds
Now to find the maximum height reaches, replace t with 11.2 in the equation
h(t) = -4.9.t² +110.t + 2
h(t) = - 1/2 gt² + v₀t + h₀
h(t) = - 1/2 (9.8).t² + 110.t + 2 ; h(t) = -4.9.t² +110.t + 2
The time needed to reach the maximum height is when the derivative
of h(t) is equal to 0:
h'(t) = 2(-4.9).t + 110 → h'(t) = -9.8.t + 110 = 0 and t = 11.22 seconds
Now to find the maximum height reaches, replace t with 11.2 in the equation
h(t) = -4.9.t² +110.t + 2