Respuesta :

first, you simplify 12x=3y+7. Subrtact 7 from both side, get 12x-7=3y. Divide 3 from both sides, get y=4x-(7/3). Your 2 equations are y=4x-1 and y=4x-7/3. The 2 lines are parallel, since they have the same slope but different b's.

Answer:

Neither is the answer.

Step-by-step explanation:

If a line y = m₁x + c₁ and y = m₂x + c₂ are perpendicular to each other then m₁ × m₂ = -1

If both the lines are parallel to each other then m₁ = m₂

Now two lines have been given as

y = 4x - 1 ----------(1)

12x = 3y + 7

3y = -12x + 7

y = -4x + [tex]\frac{7}{3}[/tex]------(2)

Now from equation (1) and equation (2),

m₁ = 4 and m₂ = -4

Since m₁ ≠ m₂

Therefore, these lines are not parallel

m₁ × m₂ = 4 × (-4) = -16

Therefore, both the lines are neither parallel nor perpendicular.