f(x) :
(-1,-5) (0,-1).....we will use slope formula (y2 - y1) / (x2 - x1)
slope = (-1 - (-5) / (0 - (-1) = (-1 + 5) / (0 + 1) = 4/1 = 4
y = mx + b
slope(m) = 4
(-1,-5)...x = -1 and y = -5
sub and find b, the y int
-5 = 4(-1) + b
-5 = -4 + b
-5 + 4 = b
-1 = b
so ur equation is : y = 4x - 1.....where ur slope is 4 and ur y int is -1
g(x) :
g(x) = 4x + 3.....In y = mx + b form, the slope is in the m position and the y int is in the b position......slope is 4 and y int is 3
Both the table f(x) and the equation g(x) have the same slope.....it is 4
The greater y int would be g(x)...because it has a y int of 3, whereas, f(x) has a y int that is -1