Respuesta :

WojtekR
[tex]$\dfrac{\sqrt[3]{x^8}}{\left(x^4\right)^\frac{1}{3}}=\dfrac{x^\frac{8}{3}}{x^{4\cdot\frac{1}{3}}}=\dfrac{x^{\frac{8}{3}}}{x^{\frac{4}{3}}}=x^{\frac{8}{3}-\frac{4}{3}}=x^{\frac{8-4}{3}}=\boxed{x^{\frac{4}{3}}}[/tex]

so:

[tex]y=\dfrac{4}{3}[/tex]