What is the concentration of a solution made by diluting 65 ml of 6.0 m hcl to a final volume of 750 ml?

Remember that the concentration of a solution, is the calculus of dividing the amount of solute, could be in grams, mililiters, moles, by the amount of solvent in which the solute is going to be dissolved, in this case we will use the data provided to solve with the next formula:

[tex]C1V1=C2V2\\C2=\frac{C1*V1}{V2}\\ C2=\frac{65*6}{750}\\ C2=0,52[/tex]

So the concetration will be 0,52 m

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Eduard22sly Eduard22sly · Answer 2 · 2021-09-10T18:44:25+02:00

The concentration of the diluted solution is 0.52 M

Dilution is simply reducing the concentration of a solution by the application of water.

The concentration of a diluted solution can be obtained by using the following formula:

C₁V₁ = C₂V₂

Where:

C₁ => is the concentration of the stock solution

V₁ => is the volume of the stock solution

C₂ => is the concentration of the diluted solution

V₂ => is the volume of the diluted solution.

With the above formula, we can obtain the concentration of the diluted solution as follow:

Volume of stock solution (V₁) = 65 mL

Concentration of stock (C₁ ) = 6 M

Volume of diluted solution (V₂) = 750 mL

Concentration of diluted solution (C₂) =?

C₁V₁ = C₂V₂

6 × 65 = C₂ × 750

390 = C₂ × 750

Divide both side by 750

C₂ = 390 / 750

C₂ = 0.52 M

Therefore, the concentration of the diluted solution is 0.52 M

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