Respuesta :
Given the fact that 5 out of the 15 trucks have brake problems, we can find the probability that a delivery truck has brake problems as 5/15 = 0.3333. In the sample of 4 trucks, the number of trucks that have defective brackets is a binomially distributed random variable with n = 4 and p = 0.3333. Using the formula for binomial distribution, we get P(X = 2) = 4C2 * 0.3333² * (1–0.3333)² = 0.2963.
The answer is 0.2963.
The answer is 0.2963.
Answer:
Hence, the probability is:
0.296
Step-by-step explanation:
This can be solved with the help of the binomial probability as:
[tex]P(x=r)=n_C_rp^r(1-p)^{n-r}[/tex]
where n denote the quantity which are chosen.
r denote the quantity whose probability is to be determined or success.
and p denote the probability of success.
with n=4 since 4 trucks are randomly selected.
p=5/15=1/3 ( As 5 have brake problems out of total 15 trucks)
1-p=10/15=2/3
r=2 ( since we are asked to find the probability that 2 of those tested have defective brakes)
Hence, the probability is:
[tex]P(x=2)=4_C_2(\dfrac{1}{3})^2(\dfrac{2}{3})^2\\\\\\P(x=2)=\dfrac{4!}{2!\times (4-2)!}\times \dfrac{1}{9}\times \dfrac{4}{9}\\\\\\P(x=2)=0.296[/tex]
Hence, the probability is:
0.296
