GEOin6th
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20 PTS

line segment jk and jl in the xy-coordinate both have a common endpoint j(-4,11) and midpoints an mv1(2,16) and mv2 (-3,5) respectively.

What is the distance between mv1 and mv2? round to the nearest tenth

Respuesta :

WojtekR
We know that:

[tex]MV_1=(2,16)\\\\MV_2=(-3,5)[/tex]

so the distance:

[tex]d(MV_!,MV_2)=\sqrt{(-3-2)^2+(5-16)^2}=\sqrt{(-5)^2+(-11)^2}=\\\\=\sqrt{25+121}=\sqrt{146}\approx\boxed{12.1}[/tex]