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In the following reaction, how many grams of oxygen will react with 10.47 grams of benzene (C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O The molar mass of benzene is 78.1074 grams and that of O2 is 32 grams. 32.17 grams

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32.17 grams of oxygen.

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You have 10.47 grams of benzene. Dividing by its molar mass of 78.1074 means that you have 10.47/78.1074 = 0.134046 moles of benzene. Looking at the reaction, for every 2 moles of benzene, you need 15 moles of O2. So 0.134046 / 2 * 15 = 1.005346 moles of O2 is needed to consume all the benzene. And then multiply by O2's molar mass and you get 1.005346 * 32 = 32.17109 which when rounded to the nearest hundredth, gives you 32.17 grams.

Answer: The mass of oxygen atom that will react with given amount of benzene will be 32.17 grams.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]   .....(1)

For Benzene:

Given mass of benzene = 10.47 g

Molar mass of benzene = 78.1074 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of benzene}=\frac{10.47g}{78.1074g/mol}=0.134mol[/tex]

For the given chemical reaction:

[tex]2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O[/tex]

By stoichiometry of the reaction:

2 moles of benzene reacts with 15 moles of oxygen.

So, 0.134 moles of benzene will react with [tex]\frac{15}{2}\times 0.134=1.005mol[/tex] of oxygen.

Now, to calculate the mass of oxygen, we use equation 1

Moles of oxygen gas = 1.005 mol

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

[tex]1.005mol=\frac{\text{Mass of oxygen}}{32g/mol}\\\\\text{Mass of oxygen}=32.17g[/tex]

Hence, the mass of oxygen atom that will react with given amount of benzene will be 32.17 grams.

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