Respuesta :
One by one.
1) What force (in newtons) is required to accelerate a body with a mass of 32 kilograms at a rate of 12 m/s2?
Data:
m = 32 kg
a = 12 m/s^2
Principle / formula: Secon Law of Newton, F = m*a
=> F = 32 kg * 12 m/s^2 = 384 N
2) If a body with a mass of 4 kg is moved by a force of 20 N, what is the rate of its acceleration?
Data:
m = 4 kg
F = 20 N
a =?
Formula: F = m*a => a = F/m = 20N / 4kg = 5 m/s^2
3) A car with a mass of 1,500 kg is traveling at a speed of 30 m/s. What force must be applied to stop the car in 3 seconds?
Data:
m = 1500 kg
Vo = 30 m/s
Vf =?
t = 3 seconds
F = ?
Formulas:
F = m*a
a = [Vf - Vo]/t
=> a = [30m/s - 0] / 3 s = 30m/s / 3s = 10 m/s^2
=> F = 1500 kg * 10 m/s^2 = 15,000 N
4) If a suitcase has a mass of 20 kg, what is the force of gravity acting on it?
F = m * g = 20 kg * 9.8 m/s^2 = 196 N
5) On the moon, what would be the force of gravity acting on an object that has a mass of 7 kg?
Use g in the moon 1.625 m/s^2
F = m * g = 7 kg * 1.625 m/s^2 = 11.735 N
6) On earth, what is a child’s mass if the force of gravity on the child’s body is 100 N?
F = m * g => m = F / g = 100N / 9.8 m/s^2 = 10.2 kg
1) What force (in newtons) is required to accelerate a body with a mass of 32 kilograms at a rate of 12 m/s2?
Data:
m = 32 kg
a = 12 m/s^2
Principle / formula: Secon Law of Newton, F = m*a
=> F = 32 kg * 12 m/s^2 = 384 N
2) If a body with a mass of 4 kg is moved by a force of 20 N, what is the rate of its acceleration?
Data:
m = 4 kg
F = 20 N
a =?
Formula: F = m*a => a = F/m = 20N / 4kg = 5 m/s^2
3) A car with a mass of 1,500 kg is traveling at a speed of 30 m/s. What force must be applied to stop the car in 3 seconds?
Data:
m = 1500 kg
Vo = 30 m/s
Vf =?
t = 3 seconds
F = ?
Formulas:
F = m*a
a = [Vf - Vo]/t
=> a = [30m/s - 0] / 3 s = 30m/s / 3s = 10 m/s^2
=> F = 1500 kg * 10 m/s^2 = 15,000 N
4) If a suitcase has a mass of 20 kg, what is the force of gravity acting on it?
F = m * g = 20 kg * 9.8 m/s^2 = 196 N
5) On the moon, what would be the force of gravity acting on an object that has a mass of 7 kg?
Use g in the moon 1.625 m/s^2
F = m * g = 7 kg * 1.625 m/s^2 = 11.735 N
6) On earth, what is a child’s mass if the force of gravity on the child’s body is 100 N?
F = m * g => m = F / g = 100N / 9.8 m/s^2 = 10.2 kg
Answer: 1. F = ma
F = 32 kg × 12 m/s2
F = 384 N
2. a=Fm
a
=
F
m
a=20 N4 kg
a
=
20
N
4
kg
a = 5 m/s2
3. Keep in mind that when the car stops, the final velocity is zero. Use the formula for final velocity to calculate the acceleration.
v2 = v1 + at
0 m/s = 30 m/s + (a × 3 s)
0 = 30 + 3a
Subtract 3a from both sides of the equation.
0 − 3a = 30 + 3a − 3a
−3a = 30
Divide both sides of the equation by –3 to solve for a.
a = –10 m/s
The acceleration is negative, which means that the car is slowing down. The force needed to cause such acceleration can be calculated as follows:
F = ma
F = 1,500 kg × (–10 m/s2)
F = –15,000 N
A deceleration or braking force of –15,000 N must be applied to stop the car in 3 seconds.
4. F = mg
F = 20 kg × 9.8 m/s2
F = 196 N
5. F=mg6
F
=
m
g
6
F=7 kg×9.8 m/s26
F
=
7
kg
×
9.8
m/s
2
6
F=68.66
F
=
68.6
6
F = 11.43 N
6. m=Fg
m
=
F
g
m=100 N9.8 m/s2
m
=
100
N
9.8
m/s
2
m = 10.2 kg
Explanation: Pen foster
