Respuesta :
Answer:
The flask contains [tex]9.4094\times 10^{22} molecules[/tex] of air.
Explanation:
Volume of the air in fridge = 3.50 L
Moles of air in fridge = n
At STP, 1 mole of gas occupies 22.4 L of volume.
Then n moles of gas will occupy:
[tex]n\times 22.4L=3.50 L[/tex]
[tex]n=\frac{3.50 L}{22.4 L}=0.15625 mol[/tex]
[tex]1 mol = 6.022\times 10^{23} [/tex] atoms/molecules
Number molecules of gases in the flask:
[tex]0.15625 \times 6.022\times 10^{23}=9.4094\times 10^{22} molecules[/tex]
The flask contains [tex]9.4094\times 10^{22} molecules[/tex] of air.
At standard temperature and pressure the number of gaseous molecules in the flask is [tex]\rm \bold { 9.409\times 10^2^2}[/tex].
The volume of the flask = 3.5 L
At STP gas occupy 22.4 L volume.
Number of moles in the flask,
[tex]\rm \bold { n =\frac{3.5}{22.4} }\\\rm \bold { n =0.1562 mol}[/tex]
Since, [tex]\rm \bold{ 1mol = 6.02\times 10^2^3}\\[/tex]
The number of gaseous molecules in the flask will be,
[tex]\rm \bold {\Rightarrow 1.562\times 6.02\times 10^2^3}\\\rm \bold {\Rightarrow 9.409\times 10^2^2}[/tex]
Hence, we can conclude that at standard temperature and pressure the number of gaseous molecules in the flask is [tex]\rm \bold { 9.409\times 10^2^2}[/tex].
To know more about Mole concept, refer to the link:
https://brainly.com/question/2350371?referrer=searchRe
