Respuesta :

LammettHash
[tex]\begin{cases}x=1+t\\y=2t\\z=-3t\end{cases}\implies x+y-z=(1+t)+2t-(-3t)=-4[/tex]
[tex]\implies6t+1=-4\implies t=\dfrac12[/tex]

[tex]\implies p=(x,y,z)=(1+t,2t,-3t)\implies p=\left(\dfrac32,1,-\dfrac32\right)[/tex]