Distance = 8.37 meters.
Direction = 55.5 degrees.
Let's work backwards from the described putts. The 4 putts were
1. 10 meters SW
2. 3 meters N
3. 4 meters SE
4. 0.5 meters W
So from the hole, let's go 0.5 meters E
Ball at (0.5, 0)
Now let's go 4 meters NW, leaving the ball at (0.5 - 2sqrt(2), 2sqrt(2))
Now go 3 meters S, leaving the ball at (0.5 - 2sqrt(2), 2sqrt(2) - 3)
Finally, go 10 meters NE, leaving the ball at (0.5 +3sqrt(2), 7sqrt(2)-3)
x = 0.5 + 3sqrt(2) = 4.74 meters
y = 7sqrt(2)-3 = 6.90 meters
Using the Pythagoras's theorem, the distance of the ball from the hole was
d = sqrt(4.74^2 + 6.90^2) = 8.37 meters
The tangent of the angle is 6.90/4.74 = 1.455.
The arc tangent (or inverse tangent) of 1.455 = 55.5 degrees