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If it is 6.00 M (molar) NaOH, there are 6 moles per liter. Use this equation to find the amount of moles in 250 mL

Molarity x Liters = Moles

We have the molarity already (6.00 M), so we just need to convert mL to L.

250 mL x 1 Liter/1000 mL = .25 L

Set up the equation

6.00 M x .25 L = 1.5 moles

Explanation:

As molarity is the number of moles present in liter of solution. So, convert given volume into liter as follows.

                [tex]250 ml \times \frac{1 L}{1000 ml}[/tex]   (as 1 L = 1000 ml)

               = 0.25 L

Therefore, number of moles of solute present will be calculated as follows.

       Molarity = [tex]\frac{\text{no. of moles}}{volume}[/tex]

                      6.00 M = [tex]\frac{\text{no. of moles}}{0.25 L}[/tex]

                    no. of moles = 1.5 mol

Hence, number of moles of solute in 250.0 ml of 6.00 M NaOH is 1.5 mol.

Now, calculate the mass of solute as follows.

           No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                    1.5 mol = [tex]\frac{mass}{39.99 g/mol}[/tex]        

                 mass = 59.98 g

Thus, we can conclude that mass of solute in 250.0 ml of 6.00 M NaOH is 59.98 g.

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