if we take 115 to be the 100%, how much is 266 off of it then?
[tex]\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
115&100\\
266&p
\end{array}\implies \cfrac{115}{266}=\cfrac{100}{p}\implies p=\cfrac{266\cdot 100}{115}
\\\\\\
p\approx 231.3[/tex]
so 266 is about 231% of 115, which is 131% more than 115.