Answer:
To obtained the smallest number multiply the number with [tex](10)^{-1}[/tex].
Step-by-step explanation:
Given : [tex](10)^{-1},\ (10)^0,\ (10)^1,\ (10)^2[/tex]
We have to find when we multiply any number with the given number which number will give the smallest value.
Consider the given numbers,
[tex](10)^{-1},\ (10)^0,\ (10)^1,\ (10)^2[/tex]
We find the values of each number one by one,
1) consider [tex](10)^{-1}[/tex], using property of exponents [tex]a^{-m}=\frac{1}{a^m}[/tex], we have
[tex](10)^{-1}=\frac{1}{10}=0.1[/tex]
2) [tex](10)^0[/tex] we know any thing to power 0 is always 1.
[tex](10)^0=1[/tex]
3) [tex](10)^1[/tex] is same as itself that is 10.
4) [tex](10)^2[/tex] is [tex](10)\times 10=100[/tex]
Thus, To obtained the smallest number multiply the number with [tex](10)^{-1}[/tex].
