Jena82
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Write the equation of a line with a slope of 3 and a y-intercept of 1. y = x + 3 y = 3x + 1 3x + y = 1 x + 3y = 1

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RedRicin
If you know the the slope and y-intercept of a line you can write its equation in slope-intercept form, which is written like this:
 where  is the slope and  is the y-intercept
In this case, since the slope is 3 and the y-int. is 1, our equation must be
[tex]\boxed{y=3x+1}[/tex]
Y=mx+b is the general equation of a line. M is the slop and b is the y-intercept. Therefore, y=3x+1