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In a calorimeter, 40 g of ice absorbs heat with an enthalpy of fusion of 334 J/g.
What is the heat absorbed in kJ?
Convert your answer to kJ and round to two decimal places.
Enter the number only; no units.
Your Answer:

Respuesta :

Answer: Answer is 13.36 kJ.

Explanation:  First, we’ll find the heat absorbed by the ice using the enthalpy of fusion:

Enthalpy of fusion of ice = 334 J/g 12.

Mass of ice = 40 g.

Heat absorbed by the ice = (Mass) × (Enthalpy of fusion).

Heat absorbed by the ice = 40 g × 334 J/g = 13360 J.

Now, let’s convert this to kilojoules (kJ):

1 kJ = 1000 J.

Heat absorbed in kJ = 13360 J / 1000 = 13.36 kJ (rounded to two decimal places).

Hence, the heat absorbed by the ice during fusion is approximately 13.36 kJ.

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