Respuesta :
Answer:
a. Amount of TiCl4 reacted: 0.005263 moles
b. Amount of Ti formed: 0.005263 moles
c. Mass of Ti formed: 0.2526 grams
d. Mass of NaCl formed: 1.2316 grams
e. Mass of Ti formed from 1 tonne of TiCl4: 252,631.57 grams
Explanation:
Given:
Mass of TiCl4 = 1.0 g
Excess sodium (meaning enough sodium to react with all TiCl4)
Atomic masses: Na = 23, Ti = 48, Cl = 35.5
Calculations:
a. Amount of TiCl4 reacted:
Calculate the molar mass of TiCl4: 48 (Ti) + (4 * 35.5) (Cl) = 190 g/mol
Convert mass of TiCl4 to moles: 1.0 g / 190 g/mol = 0.005263 moles
b. Amount of Ti formed:
The stoichiometry of the reaction shows a 1:1 ratio between TiCl4 and Ti: TiCl4 + 4Na -> Ti + 4NaCl
Therefore, the amount of Ti formed is equal to the amount of TiCl4 reacted: 0.005263 moles
c. Mass of Ti formed:
Multiply the moles of Ti by its atomic mass: 0.005263 moles * 48 g/mol = 0.2526 grams
d. Mass of NaCl formed:
The stoichiometry shows a 4:1 ratio between TiCl4 and NaCl: TiCl4 + 4Na -> Ti + 4NaCl
Calculate the moles of NaCl formed: 0.005263 moles TiCl4 * 4 = 0.021052 moles NaCl
Calculate the mass of NaCl formed: 0.021052 moles * (23 Na + 35.5 Cl) g/mol = 1.2316 grams
e. Mass of Ti formed from 1 tonne of TiCl4:
Convert 1 tonne to grams: 1 tonne * 1000 kg/tonne * 1000 g/kg = 1,000,000 grams
Calculate the moles of TiCl4 in 1 tonne: 1,000,000 g / 190 g/mol = 5263.16 moles
Since the stoichiometry is 1:1 for TiCl4 and Ti, the moles of Ti formed is the same: 5263.16 moles
Calculate the mass of Ti formed: 5263.16 moles * 48 g/mol = 252,631.57 grams
Therefore:
a. Amount of TiCl4 reacted: 0.005263 moles
b. Amount of Ti formed: 0.005263 moles
c. Mass of Ti formed: 0.2526 grams
d. Mass of NaCl formed: 1.2316 grams
e. Mass of Ti formed from 1 tonne of TiCl4: 252,631.57 grams