Answer:
C. 3.6
Explanation:
To find the magnitude of a vector, you use the formula:
Magnitude = √(x^2 + y^2 + z^2)
where x, y, and z are the components of the vector.
For the given vectors:
Vector 1: (2.0, -3.0, -4.0)
Vector 2: (6.0, -5.0, -9.0)
We calculate the magnitude of each vector separately:
For Vector 1:
Magnitude = √(2.0^2 + (-3.0)^2 + (-4.0)^2)
= √(4 + 9 + 16)
= √29
For Vector 2:
Magnitude = √(6.0^2 + (-5.0)^2 + (-9.0)^2)
= √(36 + 25 + 81)
= √142
Now, we compare the magnitudes:
√29 ≈ 5.39
√142 ≈ 11.92
Thus, the magnitude of Vector 1 is smaller. The closest option to the magnitude of Vector 1 is:
C. 3.6
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