Answer:
[tex]23\times6[/tex]
Step-by-step explanation:
[tex]\text{Solution:}\\\text{Let the rectangle's length be }l\text{ and it's width be }w.\\\text{1st condition:}\\l=3w+5.......(1)\\\text{2nd condition:}\\\text{Perimeter = 58mm}\\\text{or, }2(l+w)=58\\\text{or, }2l+2w=58\\\text{Using equation(1),}\\2(3w+5)+2w=58\\\text{or, }6w+10+2w=58\\\text{or, }8w=48\\\therefore\ w=6\text{mm}[/tex]
[tex]\therefore\ \text{Width of rectangle = 6mm}\\\text{Now, length of rectangle}(l)=3w+5=3(6)+5=23\text{mm}[/tex]
[tex]\text{So the dimensions of rectangle are }23\times6.[/tex]
