With explainantion only or i will report if I like I will mark you as brainliast

The base of a triangular field is three times of its altitude. If the cost of levelling the field at ₹75 per hectare is ₹ 1012.50, find its base and corresponding height.​

Respuesta :

Answer :

  • base = 9units
  • altitude = 3 units

let the altitude of the triangle be x then the base would be 3x.

we know that.

the area of a triangle is given by, area = 1/2" base altitude

  • area = 1/2*3x*x
  • area = 1/2*3x^2 ... (1)

atq. the cost of levelling the field at ₹75 per hectare is ₹1012.50

it means the area of the triangle would be

  • area = total cost /per hectare cost
  • area = 1012.50/₹ 75
  • area = 13.5 ...(2)

plugging in the measure of the area in eq(1),

  • 13.5 = 1/2*3x^2
  • 3x^2 = 13.5*2
  • 3x^2 = 27
  • x^2 = 27/3
  • x^2 = 9
  • x = √9
  • x = 3

and

  • 3x = 3*3 = 9 units

hence, the corresponding height of the triangle is 3 units & the base equals 9 units .

Answer:

Base = 900 meters

Height = 300 meters

Step-by-step explanation:

The area of a triangle with base b and height h is given by the formula:

[tex]\textsf{Area of a triangle}=\dfrac{1}{2}bh[/tex]

The altitude of a triangle is its height.

Given that the base (b) is three times the height (h), then b = 3h. Substitute this into the area formula:

[tex]\textsf{Area of triangular field}=\dfrac{1}{2}3h\cdot h\\\\\\\textsf{Area of triangular field}=\dfrac{3}{2}h^2[/tex]

To find the area of the triangular field, we can the total cost of ₹1012.50 by the rate of ₹75 per hectare:

[tex]\textsf{Area of triangular field}=\dfrac{\textsf{Total cost}}{\textsf{Rate}}\\\\\\\textsf{Area of triangular field}=\dfrac{1012.50}{75}\\\\\\\textsf{Area of triangular field}=13.5\; \sf hectares[/tex]

As one hectare is equal to 10,000 m², then the area of the field in square meters is:

[tex]\textsf{Area of triangular field}=135000\; \sf m^2[/tex]

To find the height (altitude) of the triangular field, substitute the formula for area into this equation and solve for h:

[tex]\dfrac{3}{2}h^2=135000\\\\\\\dfrac{3}{2}h^2\cdot \dfrac{2}{3}=135000\cdot \dfrac{2}{3}\\\\\\h^2=90000\\\\\\\sqrt{h^2}=\sqrt{90000}\\\\\\h=300\;\sf meters[/tex]

Therefore, the height of the field is 300 meters.

Since the base is three times the height, then:

[tex]\textsf{Base}=3 \cdot 300 = 900\; \sf meters[/tex]

So, the base is 900 meters.