if no base is stated, then assume base 10
[tex]log(x)=log_{10}(x)[/tex]
rememer
[tex]a=log_b(c)[/tex] translates to [tex]b^a=c[/tex]
so
[tex]r=log(x)[/tex] or
[tex]r=log_{10}(x)[/tex] translates to [tex]10^r=x[/tex]
so when r=7.9, what is x
[tex]10^r=x[/tex]
[tex]10^{7.9}=x[/tex]
79432823.472428=x
round to nearest ???
thousanth? 79432823.472=x
hundreth? 79432823.47=x
tenth? 79432823.5=x