Respuesta :

apologiabiology
assuming you mean [tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]

subsitute
[tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]
[tex]f(7)=\frac{3}{7+2}-\sqrt{7-3}[/tex]
[tex]f(7)=\frac{3}{9}-\sqrt{4}[/tex]
[tex]f(7)=\frac{1}{3}-2[/tex]
[tex]f(7)=\frac{1}{3}-\frac{6}{3}[/tex]
[tex]f(7)=\frac{-5}{3}[/tex]
f(7)≈1.6666
round
f(7)=1.67
lublana

Answer:

-1.67

Step-by-step explanation:

We are given  that

[tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]

We have to find the value of f(7).

Substitute x=7

Then, we get

[tex]f(7)=\frac{3}{7+2}-\sqrt{7-3}[/tex]

[tex]f(7)=\frac{3}{9}-\sqrt4[/tex]

[tex]f(7)=\frac{1}{3}-2[/tex]

[tex]f(7)=\frac{1-6}{3}=-\frac{5}{3}=-1.67[/tex]

Hence, f(7)=-1.67

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