Given that the sides of a right angle measures 4sqrt15 and 7sqrt6, thus the possible size of the third side will be:
using Pythagorean theorem:
c^2=a^2+b^2
c^2=(4sqrt15)^2+(7sqrt16)^2
c^2=4^2*15+7^2*16
c^2=240+784
c^2=1024
hence;
c=sqrt1024
c=32
Th possible third side is 32