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03-08-2017
Mathematics

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Evaluate ƒ(x) = –x 2 + 1 for x = –3.

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03-08-2017

ƒ(x) = –x^2 + 1 for x = –3.

Substitute x for -3

ƒ(x) = –( -3)^ 2 + 1
ƒ(x) = -9 + 1
ƒ(x) = -8

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