h(t)=-16t^2+25t
The maximum height occurs at the vertex of the quadratic.
The vertex of a quadratic is always at:
(x,y)=(-b/(2a), (4ac-b^2)/(4a))
So the maximum height is:
(4ac-b^2)/(4a), and in our equation a=-16, b=25, and c=0 so
hmax=(0-25^2)/(-64)
hmax=-625/-64
hmax=9.765625
hmax≈9.8 ft (to nearest tenth of a foot)
