okay so just use it as an equation. if 2sin0 + 3^(1/2) = 0 2 sin0 = - 3^(1/2) then sin0 = (-3^ (1/2))/2 do sin^-1(-[tex] \frac{-\sqrt{3}}{2} [/tex]) = -1/3pi we want it between 0 < x < 2pi so add 2pi (equivalent to 360degrees) = 5/3pi and to find the second value, (2pi - 5/3pi) + pi = 4/3pi answers are 5/3pi and 4/3pi
