Two charges separated by a distance of 1 meter exert a 2-n force on each other. if the magnitude of each charge is doubled, the force on each charge is

Respuesta :

TammyP
Force will be 4 times bigger

Answer:

8N

Explanation:

coulomb's law is applied in finding the solution to this problem

the law states that "for two point charges separated by a finite distance, the magnitude of force between them id directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

mathematically, F= kq₁q₂/ r²

inital force exerted, F=2N

distance =1m

2=kq₁q₂/ (1)²

2× 1=k × q₁q₂

k=2/q₁q₂

when magnitude of charge is doubled

F¹=kq₁q₂/ r²

new force F¹ =[tex]\frac{2}{q_{1}q_{2} }[/tex] ×[tex]\frac{2q_{1} 2q_{2} }{1^{2} }[/tex]

                     =2×2×2

                      =8N