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airplane releases a ball as it flies parallel to the ground at a height of 195m, the ball lands on the ground at exactly 195m from the release piont, calculate the speed v of the plane

Respuesta :

sophiemcdo
h=195; x=195
v=x/t. If someting falls down but hast already a certain Speed in a horizontal direction you have to differ between the horizontal and the vertical Speed/ acceleration: x=v×t; y= 1/2×g×t^2. y and h are usually the Same.
h=1/2×g×t^2. t^2=(2×h):g. t=√(2×h):g
v=x/√(2×h):g

Answer:

Velocity of plane = 30.93 m/s

Explanation:

Considering vertical motion of ball

    Initial velocity, u =  0 m/s

   Acceleration , a = 9.81 m/s²

   Displacement, s = 195 m

   We have equation of motion s= ut + 0.5 at²

   Substituting

       s= ut + 0.5 at²

       195 = 0 x t + 0.5 x 9.81 x t²

        t = 6.31 seconds

Now considering horizontal motion of ball

   Acceleration , a = 0 m/s²

   Displacement, s = 195 m

   Time, t = 6.31 s

   We have equation of motion s= ut + 0.5 at²

   Substituting

       s= ut + 0.5 at²

       195 = u x 6.31 + 0.5 x 0 x 6.31²

        u = 30.93 m/s

Velocity of plane is horizontal initial speed of ball = 30.93 m/s

Velocity of plane = 30.93 m/s

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