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If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?

2LiClO3 → 2LiCl + 3O2


41.1 g O2
20.6 g O2
9.13 g O2
6.85 g O2

Respuesta :

RickyChen
LiClO3 has mole of mass of 90 g/mol

So 38.7 g means 0.43 mol

Since in this reaction, LiClO3 : O2 = 2:3, then it will produce 0.43*3/2 = 0.645 mol O2

So it is equivalent to 0.645 * 32 = 20.64 g O2
laffy454544
The answer to your question is 20.6

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