Richard has just been given a 4-question multiple-choice quiz in his history class. each question has four answers, of which only one is correct. since richard has not attended class recently, he doesn't know any of the answers. assuming that richard guesses on all four questions, find the indicated probabilities. (round your answers to three decimal places.) (a) what is the probability that he will answer all questions correctly

Respuesta :

To solve the following problem, we must use the binomial probability equation. This is expressed mathematically as:

P (r) = [n!/(n-r)! r!] * p^r * q^(n-r)

where,

n = total number of questions = 4

r = number of correct questions = 4

p = probability of success = 25% = 0.25

q = probability of failure = 0.75

Therefore substituting the values into the given equation will give us:

P (r = 4) = [4! / 0! 4!] * 0.25^4 * 0.75^0

P (r = 4) = 3.906 * 10^-3 = 0.391%          

Answer: Richard only has 0.391% to answer all questions correctly by guessing.

The probability of answering all the question correctly is [tex]\boxed{\bf \dfrac{1}{256}}[/tex]

Further Explanation:

Given:

The total number of question is [tex]4[/tex].

Each question has [tex]4[/tex] options and one is correct.

Concept used:

Probability is defined as the ratio of number of favorable outcomes to number of total outcomes.

[tex]\boxed{\text{Probability}=\dfrac{\text{favorable outcomes}}{\text{total outcomes}}}[/tex]

Calculation:

The probability of getting the correct answer is calculated as follows:

[tex]\begin{aligned}P&=\dfrac{1}{4}\\&=0.25\end{aligned}[/tex]

The probability of getting the incorrect answer is calculated as follows:

[tex]\begin{aligned}P&=1-\dfrac{1}{4}\\&=1-0.25\\&=0.75\end{aligned}[/tex]

The formula for probability of answering all question correctly is as follows:

[tex]\boxed{P'=^nC_{r}P^{r}(1-P)^{n-r}}[/tex]

Here, [tex]n[/tex] is number of question and [tex]r[/tex] is number of correct answer, [tex]P'[/tex] is the probability of answering all question correctly.

Solve the above equation to obtain probability of answer all question correctly.

Substitute [tex]4[/tex] for [tex]n[/tex], [tex]0.25[/tex] for [tex]P[/tex] and [tex]4[/tex] for [tex]r[/tex] in above equation to obtain probability of answering all question correctly.

[tex]\begin{aligned}P'&=^4C_{4}(0.25)^{4}(1-0.25)^{4-4}\\&=\dfrac{4!}{(4-4)!\cdot 4!}\left(\dfrac{25}{100}\right)^{4}(0.75)^{0}\\&=\left(\dfrac{1}{4}\right)^{4}\\&=\dfrac{1}{256}\end{aligned}[/tex]  

Therefore, the probability of the correct answer is [tex]0.25[/tex].

The probability of the incorrect answer is [tex]0.75[/tex].

The probability of answering all question correctly is [tex]\dfrac{1}{256}[/tex].

Thus, the probability of answering all question correctly is [tex]\boxed{\dfrac{1}{256}}[/tex].

Learn more:

1. Simplification: https://brainly.com/question/1602237

2. Quadratic equation: https://brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Probability

Keywords: Probability, Question, Richard, multiple choice, four answer, class, attend, guesses, correctly answer, favorable outcomes, total outcomes.