One hundred and fifty tickets were sold for a basketball match and $560 was the total amount collected. adult tickets were sold at $4.00 each and child tickets were sold at $1.50 each. how many adult tickets and how many child tickets were sold?...
lets say (child tickets=x) and (adult tickets=y)...
with the information given we know that the total of tickets sold was 150...
(x+y=150)
and we also know that the sales was $560 and that the price for child was $1.50 and the price for adult $4.00...
((1.5)x+(4)y=560)
if we solve for y in the first equation, we get...
(y=150-x)
so now we replace the y value in the second equation with this information...
(1.5)x+(4)(150-x)=560
then we distribute the 4...
1.5x+600-4x=560
then we subtract 600 on both sides, and get...
1.5x-4x=-40
then we subtract the x, and get...
-2.5x=-40
and we divide -2.5 on both sides and get...
x=16
now we plug that in for the first equation...
(16+y=150)
subtract 16 on both sides...
y=134
so there was 16 child tickets sold and 134 adult tickets sold for the basketball math.
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