This problem might be confusing since there are a lot of given variable but we must take note that the problem only asks about the Work done by gravity, therefore:
Work = - Potential Energy
Where,
Potential Energy = mass * gravity * height
Note: It is negative since it is gravity doing the work on our system, not work being done on gravity.
Since the surface is inclined at 30 degrees, therefore:
height = 3 m * sin 30
height = 1.5 m
Calculating for Work:
Work = - 700 kg * 9.8 m / s^2 * 1.5 m
Work = - 10,290 J
Work = -10,300 J
Work do on the crate by gravity : W = -10290 J
Work is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = Work, J, Nm
F = Force, N
S = distance, m
Force and displacement of objects are vector. Multiplication of both is in accordance with the dot product concept of two vectors. Whereas W is a scalar quantity. Then if there is an angle formed by the force F and the displacement S is θ, then it can be formulated
There are 4 forces on the crate, so there are 4 work that occurs
the magnitude is the same as the force applied by the applied force (Fp) but the opposite direction
the direction is upward with F = mg
Because what is sought is only work by the force of gravity, then
we can find it from the formula of potential energy
W = ΔPE = - m. g. (h2-h1)
W = - mgh2 (h1 = 0)
Negative value are caused by the movement of objects in the opposite direction to the downward force of gravity
W = - 700. 9.8. 3 sin 30 (h2 has an angle of 30°)
W = -10290 J
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