Which of the following equations has the solution x =  all real numbers? Select one: a. 4(3 - x) + 6x = 3x + 12 - x b. 4(3 - x) + 6x = 3x + 10 - x c. 4(3 - x) + 6x = 3x + 12 + 2x d. 4(3 - x) + 6x = x + 12 - 3x

Respuesta :

a. 4(3-x) + 6x = 3x + 12 - x
    12 - 4x + 6x = 2x + 12
      2x + 12 = 2x + 12...infinite solutions <=== this one
    

b. 4(3 - x) + 6x = 3x + 10 - x
    12 - 4x + 6x = 2x + 10
    2x + 12 = 2x + 10...not this one...no solutions

c. 4(3 - x) + 6x = 3x + 12 + 2x
    12 - 4x + 6x = 5x + 12
     2x + 12 = 5x + 12....not this one...one solution

d. 4(3 - x) + 6x = x + 12 - 3x
    12 - 4x + 6x = -2x + 12
    2x + 12 = -2x + 12...not this one...one solution

The equation that has the solution x = all real numbers is given by option a) (4(3 - x) + 6x = 3x + 12 - x) and this can be determined by using the arithmetic operations.

Check all the options in order to determine which of the following equations has the solution x = all real numbers.

A) 4(3 - x) + 6x = 3x + 12 - x

Simplify the above equation separately that is:

LHS = 12 - 4x + 6x

       = 12 + 2x

RHS = 3x + 12 - x

       = 2x + 12

LHS = RHS means there is an infinite number of solutions.

B) 4(3 - x) + 6x = 3x + 10 - x

Simplify the above equation separately that is:

LHS = 12 - 4x + 6x

       = 12 + 2x

RHS = 2x + 10

LHS [tex]\neq[/tex] RHS means that there are no solutions.

C) 4(3 - x) + 6x = 3x + 12 + 2x

Simplify the above equation separately that is:

LHS = 12 - 4x + 6x

       = 12 + 2x

RHS = 5x + 12

LHS [tex]\neq[/tex] RHS means that there are no solutions.

D) 4(3 - x) + 6x = x + 12 - 3x

Simplify the above equation separately that is:

LHS = 12 + 2x

RHS = 12 - 2x

LHS [tex]\neq[/tex] RHS means that there are no solutions.

For more information, refer to the link given below:

https://brainly.com/question/13911928