Answer:
The third number in the sequence 31, 32, 33, 34 is 33
Step-by-step explanation:
let first number be the smallest number be x.
Consecutive numbers are those numbers that follow each other in order and they should have a difference of 1 between every two numbers.
Then, the four consecutive integers are x , (x+1), (x+2) , (x+3)
Given: the sum of 4 consecutive integers is 130.
From the given condition we have,
[tex]x+(x+1)+(x+2)+(x+3)=130[/tex]
Like terms states that contain the same variables raised to the same power.
Combine like terms we get,
[tex]4x+6=130[/tex]
Subtract 6 from both the sides, we get
[tex]4x+6-6=130-6[/tex]
Simplify we get,
[tex]4x=124[/tex]
Divide both sides by 4; [tex]\frac{4x}{4}= \frac{124}{4}[/tex]
On simplify we get, the value of x i.e, [tex]x=31[/tex]
the sequence we have, 31, 32, 33, 34,
therefore, the third number in the sequence is, 33.
Answer:
The answer is 33.
Step-by-step explanation:
I got this answer on Khan Academy.
Hope this helps! :)
