Respuesta :
3H₂ + N₂ = 2NH₃
V(H₂)/3 = V(NH₃)/2
V(NH₃)=2V(H₂)/3
V(NH₃)=2*4.50/3=3.00 L
3.00 L
V(H₂)/3 = V(NH₃)/2
V(NH₃)=2V(H₂)/3
V(NH₃)=2*4.50/3=3.00 L
3.00 L
Answer: The volume of ammonia gas produced will be 3 Liters.
Explanation:
At STP:
1 mole of a gas occupies 22.4 L of volume.
The chemical reaction for the formation of ammonia follows the equation:
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
It is given that nitrogen gas is present in excess. Thus, hydrogen gas is considered as limiting reagent.
By Stoichiometry of the reaction:
[tex]3\times 22.4L[/tex] of hydrogen produces [tex]2\times 22.4L[/tex] of ammonia gas.
So, 4.5 L of hydrogen gas will produce = [tex]\frac{2\times 22.4L}{3\times 22.4L}\times 4.5L=3L[/tex] of ammonia gas.
Hence, the volume of ammonia gas produced will be 3 Liters.
