The mass of the Sun is 2 × 1030 kg, and the mass of Saturn is 5.68 × 1026 kg. The distance between Saturn and the Sun is 9.58 AU. Veronica is solving the following equation to calculate the orbital period of Saturn, but there is an error in the equation. T = What should Veronica change to correct the equation?

change the position of 2 x 1030 kg and 9.58 AU
change 2 x 1030 kg to 5.68 x 1026 kg
change the square root to a cube root
change 9.58 AU to the distance in meters

It is given that the mass of the sun is 2 × 1030 kg, the mass of the Saturn is 5.68 × 1026 kg and the distance between Saturn and the Sun is 9.58 AU.

It is required to find the correct equation to calculate the orbital period of Saturn.

What is the correct equation to calculate the orbital period of Saturn?

Kepler's third law also define the time period of the planets that is the square of orbital period of revolving planets or celestial body is directly proportional to the cube of the semi -major axis.

[tex]P^{2}=A^{3}[/tex]

Rotation period of planets can be measured from the equation of velocity-distance-time that can denoted as ,

[tex]T=\frac{D}{V}[/tex]

Where, D represents the distance and V represents tangential velocity.

Average distance or we say that semi-major axis between the Saturn and sun 1.429 billion km or 9.58 AU

Therefore, the correct equation to calculate the orbital period of Saturn is [tex]T=\frac{D}{V}[/tex].

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