Respuesta :

let the fluid ounces of water that remain in beaker=x
then,
total fluid ounces of water=water poured+water remaining
so,
water remaining=total water-water poured
x= 5 2/3 - 3 1/3

carlosego

For this case we have the following data:

  • Shelly has a beaker with [tex]5 \frac{2}{3}[/tex] fluid ounces of water.
  • She pours out [tex]3 \frac{1}{3}[/tex] fluid ounces of water.

Therefore, the amount of water remaining is given by:

[tex]5 \frac {2} {3} -3 \frac {1} {3}[/tex]

Rewriting the expression we have:

[tex]5 \frac {2} {3} -3 \frac {1} {3} = 2 \frac {1} {3}[/tex]

Answer:

The expression sought is given by:

[tex]5 \frac {2} {3} -3 \frac {1} {3} = 2 \frac {1} {3}[/tex]


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