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A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. if 2 dogs are selected at random, what is the probability that both selected dogs are not littermates?

Respuesta :

konrad509
[tex]6+6\cdot1+3+3\cdot2=21[/tex] - all dogs

[tex]|\Omega|=21C2=\dfrac{21!}{2!19!}=\dfrac{20\cdot21}{2}=210\\ |A|=9C2=\dfrac{9!}{2!7!}=\dfrac{8\cdot9}{2}=36\\\\ P(A)=\dfrac{36}{210}=\dfrac{6}{35}\approx17\%[/tex]

v89y885ft6

Answer:17%

Step-by-step explanation:

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