Respuesta :
Draw the Lewis structure. Bromine has 3 bonds and two lone pairs for a trigonal bipyramidal electron geometry and an sp^3d hybridization. Fluorine is peripheral it does not require hybridization, but we often consider it to be hybridized too - it has 1 bond and 3 lone pairs for sp^3 hybridization. So the sigma bonds come from an overlap of an sp^3d orbital on Br with an sp^3 orbital on F. If you don't consider the F to be hybridized the overlap would have to be to a p orbital on the F
The hybrid sp2 orbitals are used to form the sigma bonds in BF3.
A sigma bond is formed by end to end overlap of atomic orbitals. This leads to a single bond with electron density situated along the axis of the two nuclei.
In BF3, the molecule is a triatomic molecule and the orbital hybridization state of the central boron atom is sp2. This hybrid sp2 orbitals are used to form the sigma bonds in BF3.
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