Answer:
0.68 m/s
Explanation:
The centripetal force that keeps the beetle moving in circle is given by:
[tex]F=m\frac{v^2}{r}[/tex]
where
m is the mass of the beetle
v is the tangential speed of the beetle
r is the distance of the beetle from the center of the record
In this problem, we know the force (F=0.070 N), the mass of the beetle (m=0.023 kg) and the distance from the center (r=0.15 m), therefore we can re-arrange the equation to find the tangential speed:
[tex]v=\sqrt{\frac{Fr}{m}}=\sqrt{\frac{(0.070 N)(0.15 m)}{0.023 kg}}=0.68 m/s[/tex]
