Respuesta :
The correct answer to the question is : 14.58 gram
EXPLANATION :
As per the question, the amount of heat given to the substance dQ = 350 J.
The initial temperature is given as T = 10 degree celsius.
The final temperature of the substance T' = 30 degree celsius.
Hence, change in temperature dT = T' - T
= 30 - 10 degree celsius
= 20 degree celsius.
The specific heat of the substance is given as c = [tex]1.2\ J/g^0\ C[/tex]
The mass of the substance is calculated as -
[tex]dQ=\ mcdT[/tex]
⇒[tex]m=\ \frac{dQ}{cdT}[/tex]
[tex]=\ \frac{350}{1.2\times 20}\ gram[/tex]
[tex]=\ 14.58\ gram[/tex] [ans]
The mass of the substance will be "14.58 grams".
Given:
- Heat, [tex]\Delta Q = 350 \ Joules[/tex]
- Initial temperature, [tex]T = 10^{\circ} C[/tex]
- Final temperature, [tex]T' = 30^{\circ} C[/tex]
- Change in temperature, [tex]\Delta T = T'-T[/tex]
[tex]= 30-10[/tex]
[tex]=20^{\circ} C[/tex]
- Specific heat, [tex]c = 1.2 \ J/g^{\circ} C[/tex]
Now,
The mass of substance,
→ [tex]\Delta Q = mc \Delta T[/tex]
or,
→ [tex]m = \frac{\Delta Q}{c \Delta T}[/tex]
By putting the values,
[tex]= \frac{350}{1.2\times 20}[/tex]
[tex]= 14.58 \ grams[/tex]
Thus the above approach is right.
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