Respuesta :

irspow
20x+12≥14x+30  subtract 12 from both sides

20x≥14x+18  subtract 14x from both sides

6x≥18  divide both sides by 6

x≥3
samuelonum1

Answer:

The answer is

A. x≥3

Step-by-step explanation:

This problem bothers on inequality of numbers

Step one

Given the expression we can proffer solution by solving this step wise Mathematically

Step two

20x + 12 ≥ 14x + 30

Collecting like terms we have

20x-14x ≥30-12

6x≥18

Dividing both sides by 6 we have

6x/6≥18/6

x≥3

The answer is x is greater than or equal to 3

x≥3

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