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Calculate the number of molecules present in 3.50 mol FeO2.
A. 2.11 x 1024 molecules
B. 2.107 x 1023 molecules
C. 3.50 x 1023 molecules

can anyone help me with my chemistry final plssss and only serious ppl

Respuesta :

mergl
3.5*(6.02*10^23)=2.107*10^24 molecules, so A
if you do 3.50 x 6.022x10^23 it will equal 2.1077e+24which you will then round to 2.11e+23
so the answer is 2.11e+23

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