Answer:
0.221 g of [tex]N_2O[/tex] have 0.010 mol of N
Explanation:
Mass of [tex]N_2O= 0.221\ g[/tex]
Step 1
Calculation of moles of [tex]N_2O[/tex]
[tex]Mole=\frac{Mass\ in\ g}{Molecular\ mass}[/tex]
Molecular mass of [tex]N_2O[/tex] = 14 × 2 + 16 = 44
[tex]Mole=\frac{Mass\ in\ g}{Molecular\ mass}[/tex]
[tex]=\frac{0.221}{44} = 0.005\ mol[/tex]
Calculation of moles of N
1 mol of [tex]N_2O[/tex] has 2 moles of N
0.005 mol of [tex]N_2O[/tex] will have
= 0.005 × 2 = 0.010 mol of N
So, 0.221 g of [tex]N_2O[/tex] have 0.010 mol of N
