Respuesta :
[tex]\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=46\\
d=-4\\
n=12
\end{cases}
\\\\\\
a_{12}=46+(12-1)(-4)[/tex]