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The Punnett square for a sex-linked trait is shown. Xr is the recessive allele. Based on the Punnett square, which statement is true?

Female offspring have a 50 percent chance of expressing the recessive trait.

Both male offspring will express the recessive trait.

Both female offspring will express the recessive trait.

There’s a 50 percent chance the male offspring will express the recessive trait.

Respuesta :

budwilkins
If a woman with the trait (XrXr) mates with a normal male (XY), then all (100%) of the males will express the trait, but none (0%) of the females will express it.
However, if an unaffected carrier woman (XrX) mates with a normal male (XY) then there is a 50% chance that the male offspring will express the recessive trait (XrY).

Punnett square is defined as the tabular representation of gametes, in which the prediction of genotype and phenotype of organisms is done.

Data Prediction for Punnett Square

  • In the given attachment file of Punnet Square, the linked trait is shown. Given, the genotype for the female is [tex]\rm X^r[/tex]X and males have normal XY chromosomes.  

  • The progeny that will be affected is male, while the females will be the carrier. There will be a 50% chance that the males will express the disease. Since the males have XY chromosomes, then there will be a 50% chance of expressing the disease.

Thus, the correct answer is Option D, in which the males have a chance to express the recessive linked disease.

Learn more about Punnett Square here:

https://brainly.com/question/25357981

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