Two triangles △CEA and △CDB are similar. Option A "∠BDC and ∠AED are right angles" is sufficient to prove that the given triangles are similar.
It is required to prove △CEA is similar to △CDB.
From the given figure, if we choose ∠BDC and ∠AED are right angles, then the following conclusions can be made:
- ∠BDC and ∠AED are perpendicular on the same side EC.
- AE and BD will be parallel because ∠BDC and ∠AED are equal.
- Now, AC is the intersecting side, and AE and BD are parallel. SO, the angles CAE and CBD will also be equal because they are corresponding angles.
From the above conclusions, it can be said that △CEA is similar to △CDB because they have two equal angles and AA similarity criteria are fulfilled.
Therefore, option A "∠BDC and ∠AED are right angles" is sufficient to prove that the given triangles are similar.
For more details, refer to the link:
https://brainly.com/question/20502277