Respuesta :

mergl
(9.42x10^24)/(6.02x10^23)=15.6478 mol methanol
15.6478mol(32.04g/1 mol)=501.3568g methanol

Answer: 500 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{9.42\times10^{24}}{6.023\times 10^{23}}=15.6moles[/tex]

1 mole of [tex]CH_3OH[/tex] weighs = 32.04 g/mol

Thus 15.6 moles of [tex]CH_3OH[/tex] weigh=[tex]\frac{32.04}{1}\times 15.6=500g[/tex]

Thus the mass of [tex]9.42\times10^{24}[/tex] molecules of methanol is 500 grams