The roots of the cubie equation are -2, 3, and 4.
Given
Function; [tex]\rm f(x) = x^3-5x^2 -2x + 24[/tex]
What are the roots of the cubic equation?
The equation which has the highest power 3 is called the cubic equation.
Therefore,
The roots of the cubic equation are;
[tex]\rm x^3-5x^2 -2x + 24=0\\\\ x^3-3x^2+2x^2-6x-4x^2-12x-8x+24=0\\\\ (x^2-3x+2x-6)(x-4)=0\\\\\rm (x^2-x-6)(x-4)=0\\\\(x+2)(x-3)(x-4)=0\\\\\rm x+2=0,\ x=-2\\\\\rm x-3=0, \ x=3\\\\x-4=0, x=4[/tex]
Hence, the roots of the cubie equation are -2, 3, and 4.
To know more about the Cubic equation click the link given below.
https://brainly.com/question/2400726
